Assembly of Six-Membered Vanadium Borophosphate Cluster Anions: Synthesis and Structures of (NH<sub>4</sub>)<sub>2</sub>(C<sub>2</sub>H<sub>10</sub>N<sub>2</sub>)<sub>6</sub>[BaH<sub>2</sub>O)<sub>5</sub>]<sub>2</sub>[V<sub>2</sub>P<sub>2</sub>BO<sub>12</sub>]<sub>6</sub>.8H<sub>2</sub>O and (NH<sub>4</sub>)<sub>8</sub>(C<sub>3</sub>H<sub>12</sub>N<sub>2</sub>)<sub>4</sub>[Ba(H<sub>2</sub>O)<sub>7</sub>][V<sub>2</sub>P<sub>2</sub>BO<sub>12</sub>]<sub>6</sub>.17H<sub>2</sub>O
Assembly of Six-Membered Vanadium Borophosphate Cluster Anions: Synthesis and Structures of (NH<sub>4</sub>)<sub>2</sub>(C<sub>2</sub>H<sub>10</sub>N<sub>2</sub>)<sub>6</sub>[BaH<sub>2</sub>O)<sub>5</sub>]<sub>2</sub>[V<sub>2</sub>P<sub>2</sub>BO<sub>12</sub>]<sub>6</sub>.8H<sub>2</sub>O and (NH<sub>4</sub>)<sub>8</sub>(C<sub>3</sub>H<sub>12</sub>N<sub>2</sub>)<sub>4</sub>[Ba(H<sub>2</sub>O)<sub>7</sub>][V<sub>2</sub>P<sub>2</sub>BO<sub>12</sub>]<sub>6</sub>.17H<sub>2</sub>O
- 대한화학회
- Bulletin of the Korean Chemical Society
- Vol.26 No.1
-
2005.01146 - 150 (5 pages)
- 0
Two new barium vanadium borophosphate compounds, $(NH_4)_2(C_2H_{10}N_2)_6[Ba(H_2O)_5]_2[V_2P_2BO_{12}]_6{\cdot}8H_2O$, Ba- VBPO1 and $(NH_4)_8(C_3H_{12}N_2)_4[Ba(H_2O)_7][V_2P_2BO_{12}]_6{\cdot}17H_2O$, Ba-VBPO2 have been synthesized by interdiffusion methods in the presence of diprotonated ethylenediamine and 1,3-diaminopropane. Compound Ba-VBPO1 has an infinite chain anion (${[BaH_2O)_5]_2[V_2P_2BO_{12}]_6}$$^{14-}$, whereas Ba-VBPO2 has a discrete cluster anion {[$Ba(H_2O)_7][V_2P_2BO_{12}]_6$}$^{16-}$. Crystal Data: $(NH_4)_2(C_2H_{10}N_2)_6[Ba(H_2O)_5]_2[V_2P_2BO_{12}]_6{\cdot}8H_2O$, triclinic, space group P$\overline{1}$ (no. 2), a = 13.7252(7) $\AA$, b = 15.7548(8) $\AA$, c = 15.8609(8) $\AA$, α = 63.278(1)$^{\circ}$, $\beta$ = 75.707(1)$^{\circ}$, $\gamma$ = 65.881(1)$^{\circ}$, Z = 1; $(NH_4)_8(C_3H_{12}N_2)_4[Ba(H_2O)_7][V_2P_2BO_{12}]_6{\cdot}17H_2O$, monoclinic, space group C2/c (no. 15), a = 31.347(2) $\AA$, b = 17.1221(9) $\AA$, c = 22.3058(1) $\AA$, $\beta$ = 99.303(1)$^{\circ}$, Z = 4.
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